The joint density of X and Y is given by

f(x,y)=12πe-ye-(x-y)2/20<y<,

-<x<

(a) Compute the joint moment generating function of X and Y.

(b) Compute the individual moment generating functions.

Short Answer

Expert verified

a). The joint moment generating function of Xand Yare M(X,Y)t1,t2=expt12211-t2-t1.

b). The individual moment generating functions areMXt1=expt1221-t1-1andMYt2=1-t2-1.

Step by step solution

01

Given Information (Part a)

f(x,y)=12πe-ye-(x-y)2/20<y<-<x<

02

Explanation (Part a)

M(X,Y)t1,t2=Eexpt1x+t2y

=12π0-expt1x+t2yexp(-y)exp-(x-y)22dxdy

=12π0-expt1x+t2y-y-x22-y22+xydxdy

=12π0expt2y-y-y22-exp-1x2-2bx2dxdy

=12π0expt2y-y-y22-exp-(x-b)22expb22dxdy

03

Explanation (Part a) 

=12π0expt2+t1-1y+t1222πdy

=0expt122exp-y1-t2-t1dy

=expt1220exp-y1-t2-t1dy

=expt122exp-y1-t2-t1-1-t2-t10

Therefore,

M(X,Y)t1,t2=expt12211-t2-t1

04

Final Answer (Part a)

The joint moment generating functions ofXandYare

M(X,Y)t1,t2=expt12211-t2-t1.
05

Given Information (Part b)

f(x,y)=12πe-ye-(x-y)2/20<y<

-<x<

06

Explanation (Part b)

If t2=0we have

Mxt1=expt12211-0-t1

=expt1221-t1-1

If t1=0we have

MYt2=exp0211-t2-0

=1-t2-1

07

Final Answer (Part b)

Individual moment generating functions,

If t2=0, Mxt1=expt12211-0-t1

Ift1=0,MY(t2)=1-t2-1.

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