If the distribution function of Xis given by

F(b)=0    b<012    0b<135    1b<245    2b<3910    3b<3.51    b3.5

calculate the probability mass function of X.

Short Answer

Expert verified

p(x)=12    x=0110    x=115    x=2110    x=3110    x=3.5

Step by step solution

01

Given information

F(b)=0    b<012    0b<135    1b<245    2b<3910    3b<3.51    b3.5

02

Explanation

The probability mass procedure is equivalent to zero for every particular where the distribution function is locally equivalent to some consistent. Therefore, we only have to think of facts in which function Fhas a brake.

Here,

P(0)=F(0)-P(b<0)

=12

P(1)=35-12

=110

P(2)=45-35

=15

P(3)=910-45

=110

P(3.5)=1-910

=110

03

Final answer

Probability mass function is

p(x)=12    x=0110    x=115    x=2110    x=3110    x=3.5

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