If you buy a lottery ticket in 50lotteries, in each of which your chance of winning a prize is role="math" localid="1646465220038" 1100, what is the (approximate) probability that you will win a prize

(a) at least once?

(b) exactly once?

(c) at least twice?

Short Answer

Expert verified

(a)The probability of winning prize at least once is 0.39.

(b)The probability of winning prize exactly once is 0.30.

(c)The probability of winning prize is0.09.

Step by step solution

01

Given Information (Part a)

If you buy a lottery ticket in 50lotteries, in each of which your chance of winning a prize is 1100.

02

Calculation (Part a)

We buy lottery tickets in 50lotteries, in each of which chance of a winning prize is 1100.

Find the probability of winning the prize at least once.

We use the fact that for large nand small pPoisson distribution approximates binomial distribution. Obviously np=50×1100=12. So we have:

(X1)

=1-(X=0)

=1-e-0.5

=0.39.

03

Final answer (Part a)

Probability of winning the lottery at least once is 0.39.

04

Given Information (Part b)

If you buy a lottery ticket in 50lotteries, in each of which your chance of winning a prize is 1100.

05

Calculation (Part b)

We buy lottery tickets in 50lotteries, in each of which chance of a winning prize is 1100.

Find the probability of winning the prize exactly once.

We use the fact that for large nand small pPoisson distribution approximates binomial distribution. Obviously np=50×1100=12. So we have:

(X=1)

=e-0.5·0.511!

=0.30.

06

Final answer (Part b)

Probability of winning precisely once is 0.3.

07

Given Information (Part c)

If you buy a lottery ticket in 50 lotteries, in each of which your chance of winning a prize is1100.

08

Calculation (Part c)

We buy lottery tickets in 50lotteries, in each of which chance of a winning prize is 1100.

Find the probability of winning the prize at least twice.

We use the fact that for large nand small pPoisson distribution approximates binomial distribution. Obviously np=50×1100=12. So we have:

(X2)=1-(X=0)-(X=1)

=1-e-0.5·0.500!-e-0.5·0.51!

=1-e-0.5-0.5·e-0.5=0.09.

09

Final answer (Part c)

Probability of winning at least twice is 0.09.

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