If X is a binomial random variable with expected value 6and variance2.4, find P{X=5}

Short Answer

Expert verified

P(X=5)=0.2

Step by step solution

01

Step 1: Given information

Given in the question that,Xis a binomial random variable with expected value6and variance 2.4,

02

Step 2: Explanation

We have that X~Binom(n,p).

We are given informations

EX=6np=6

Var(X)=2.4np(1-p)=2.4

Dividing the second equation with the first one, we end up with equation 1-p=2.46=0.4, so we have that p=0.6. Hence, we also have that n=10.

Finally, we are required to determine following

P(X=5)=1050.650.45=0.2

03

Step 3: Final answer

P(X=5)=0.2

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

If X has distribution function F, what is the distribution function of eX?

A box contains 5red and 5blue marbles. Two marbles are withdrawn randomly. If they are the same color, then you win \(1.10; if they are different colors, then you win -\)1.00. (That is, you lose $1.00.) Calculate

(a) the expected value of the amount you win;

(b) the variance of the amount you win.

Let Xbe a negative binomial random variable with parameters rand p, and let Ybe a binomial random variable with parameters nand p. Show that

P{X>n}=P{Y<r}

Hint: Either one could attempt an analytical proof of the preceding equation, which is equivalent to proving the identity

i=n+1i1r1pr(1p)ir=i=0r1ni×pi(1p)ni

or one could attempt a proof that uses the probabilistic interpretation of these random variables. That is, in the latter case, start by considering a sequence of independent trials having a common probability p of success. Then try to express the events to express the events {X>n}and {Y<r}in terms of the outcomes of this sequence.

Each of 500 soldiers in an army company independently has a certain disease with probability 1/103. This disease will show up in a blood test, and to facilitate matters, blood samples from all 500 soldiers are pooled and tested.

(a) What is the (approximate) probability that the blood test will be positive (that is, at least one person has the disease)? Suppose now that the blood test yields a positive result.

(b) What is the probability, under this circumstance, that more than one person has the disease? Now, suppose one of the 500 people is Jones, who knows that he has the disease.

(c) What does Jones think is the probability that more than one person has the disease? Because the pooled test was positive, the authorities have decided to test each individual separately. The first i − 1 of these tests were negative, and the ith one—which was on Jones—was positive.

(d) Given the preceding scenario, what is the probability, as a function of i, that any of the remaining people have the disease?

People enter a gambling casino at a rate of1every 2minutes.

(a)What is the probability that no one enters between 12:00and 12:05?

(b)What is the probability that at least4people enter the casino during that time?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free