Chapter 1: Q1. (page 17)

Name the property used in each step:
$\begin{matrix} 2 \cdot 3 + (4 \cdot 2 - 8) = 2 \cdot 3 + (8 - 8) \\ = 2 \cdot 3 + (0) \\ = 6 + 0 \\ = 6 \end{matrix}$

Short Answer

Expert verified

$\begin{matrix} 2 \cdot 3 + (4 \cdot 2 - 8) = 2 \cdot 3 + (8 - 8) \underline{Substitution} 4 \cdot 2 = 8 \\ = 2 \cdot 3 + (0) \underline{Substitution} 8 - 8 = 0 \\ = 6 + 0 \underline{Substitution} 2 \cdot 3 = 6 \\ = 6 \underline{Substitution} 6 + 0 = 6 \end{matrix}$

Step by step solution

– Given information.

Given expression is:

$\begin{matrix} 2 \cdot 3 + (4 \cdot 2 - 8) = 2 \cdot 3 + (8 - 8)______ \\ = 2 \cdot 3 + (0)______ \\ = 6 + 0______ \\ = 6______ \end{matrix}$

– Write the concept.

The substitution property for multiplication, addition and subtraction is:

$\begin{matrix} a \cdot b = c \\ a \pm b = c \end{matrix}$

– Write the property.

Since,

$\begin{matrix} 2 \cdot 3 + (4 \cdot 2 - 8) = 2 \cdot 3 + (8 - 8)______ \\ = 2 \cdot 3 + (0)______ \\ = 6 + 0______ \\ = 6______ \end{matrix}$

In 1^st step,

$4 \cdot 2 = 8$ (Substitution Property)

In 2^nd step,

$(8 - 8) = 0$ (Substitution Property)

In 3^rd step,

$2 \cdot 3 = 6$ (Substitution Property)

In 4^th step,

$6 + 0 = 6$ (Substitution Property)

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Name the property used in each step:
$\begin{matrix} 2 \cdot 3 + (4 \cdot 2 - 8) = 2 \cdot 3 + (8 - 8) \\ = 2 \cdot 3 + (0) \\ = 6 + 0 \\ = 6 \end{matrix}$

Short Answer

Step by step solution

– Given information.

– Write the concept.

– Write the property.

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Name the property used in each step:2⋅3+(4⋅2−8)=2⋅3+(8−8)______=2⋅3+(0)______=6+0______=6______

Short Answer

Step by step solution

– Given information.

– Write the concept.

– Write the property.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Logic and Functions

Probability and Statistics

Statistics

Pure Maths

Theoretical and Mathematical Physics

Decision Maths

Study anywhere. Anytime. Across all devices.

Name the property used in each step:
$\begin{matrix} 2 \cdot 3 + (4 \cdot 2 - 8) = 2 \cdot 3 + (8 - 8) \\ = 2 \cdot 3 + (0) \\ = 6 + 0 \\ = 6 \end{matrix}$