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Algebra 1

Carter, Cuevas, Day, Holiday, Luchin

$Math Studyset Vaia Explanations$ Math

Student Edition · 801 pages

ISBN: 9780078884801

Chapter 1: Q45. (page 44)

Find the perimeter and area of each figure.

Short Answer

Expert verified

$\begin{array}{l} Perimeter P = 18 in \\ Area A = 13.5 {in}^{2} \end{array}$

Step by step solution

01

Step 1. We have given a right angle triangle with all sides given.

$\begin{array}{l} Height h = 6 in \\ Base b = 4 \frac{1}{2} in \\ Hypoteneous l = 7 \frac{1}{2} in \end{array}$

02

Step 2. Formula used.

$\begin{array}{l} Perimeterofrightangletriangle P = h + b + l \\ Areaofrightangletriangle A = \frac{1}{2} b h \end{array}$

03

Step 3. Calculate the perimeter of the right-angle triangle.

$\begin{array}{l} Parameterofrightangletriangle P = h + b + l \\ P = 6 + 4 \frac{1}{2} + 7 \frac{1}{2} \\ P = 6 + 4.5 + 7.5 \\ P = 18 in \end{array}$

04

Step 4. Calculate the area of the right-angle triangle.

$\begin{array}{l} Areaofrightangletriangle A = \frac{1}{2} b h \\ A = \frac{1}{2} (4 \frac{1}{2}) (6) \\ A = 13.5 {in}^{2} \end{array}$

Therefore,

$\begin{array}{l} Perimeter P = 18 in \\ Area A = 13.5 {in}^{2} \end{array}$

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Most popular questions from this chapter

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