Chapter 8: Q8. (page 520)

Factor the polynomial $y^{2} + 9 y + 20$ .
$F (y + 2) (y + 10) G (y + 4) (y + 5) H (y + 3) (y + 8) J (y + 5) (y + 2)$

Short Answer

Expert verified

Factors of $y^{2} + 9 y + 20$ are $(y + 4) (y + 5)$ .

Step by step solution

Step 1. Compare.

Compare a given trinomial to $a x^{2} + b x + c$ and write the values of a,b and c.

$a = 1 b = 9 c = 20$

Step 2. List the factors.

List the factors of 20. Look for the pair of factors with a sum of 9.

Factors of	Sum of factors
1,20	21
2,10	12
4,5	9

Therefore, correct factors are 4 and 5.

Step 3. Apply factoring pattern of ax2+bx+c.

There are two numbers having product of 20 and sum of 9. The numbers are 4 and 5.

$y^{2} + 9 y + 20 = (y + m) (y + p) = (y + 4) (y + 5)$

Therefore, the factors of $y^{2} + 9 y + 20$ are $(y + 4) (y + 5)$ .

The obtained solution completely matches with option G. Therefore, option G is the required answer.

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Factor the polynomial $y^{2} + 9 y + 20$ .
$F (y + 2) (y + 10) G (y + 4) (y + 5) H (y + 3) (y + 8) J (y + 5) (y + 2)$

Short Answer

Step by step solution

Step 1. Compare.

Step 2. List the factors.

Step 3. Apply factoring pattern of ax2+bx+c.

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Factor the polynomial y2+9y+20.Fy+2y+10Gy+4y+5Hy+3y+8Jy+5y+2

Short Answer

Step by step solution

Step 1. Compare.

Step 2. List the factors.

Step 3. Apply factoring pattern of ax2+bx+c.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Logic and Functions

Pure Maths

Probability and Statistics

Mechanics Maths

Discrete Mathematics

Decision Maths

Study anywhere. Anytime. Across all devices.

Factor the polynomial $y^{2} + 9 y + 20$ .
$F (y + 2) (y + 10) G (y + 4) (y + 5) H (y + 3) (y + 8) J (y + 5) (y + 2)$