Chapter 9: Q91. (page 535)

Use elimination to solve each system of equations.
$2 x - 3 y = 2 5 x + 4 y = 28$

Short Answer

Expert verified

The solution of the given system of equations is $(4, 2)$ .

Step by step solution

Step 1. Multiply.

Multiply each side $2 x - 3 y = 2$ by 5.

$5 (2 x - 3 y) = 5 (2) 10 x - 15 y = 10$

Step 2. Multiply.

Multiply each side $5 x + 4 y = 28$ by 2.

$2 (5 x + 4 y) = 2 (28) 10 x + 8 y = 56$

Step 3. Subtract.

Subtract $10 x - 15 y = 10$ from $10 x + 8 y = 56$ . Simplify to obtain the value of y.

$(10 x + 8 y) - (10 x - 15 y) = 56 - 10 23 y = 46 \frac{23 y}{23} = \frac{46}{23} y = 2$

Step 4. Substitute.

Substitute 2 for y into $2 x - 3 y = 2$ and simplify.

$2 x - 3 (2) = 2 2 x - 6 + 6 = 2 + 6 \frac{2 x}{2} = \frac{8}{2} x = 4$

Therefore, the solution of the given system of equations is $(4, 2)$ .

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Use elimination to solve each system of equations.
$2 x - 3 y = 2 5 x + 4 y = 28$

Short Answer

Step by step solution

Step 1. Multiply.

Step 2. Multiply.

Step 3. Subtract.

Step 4. Substitute.

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Use elimination to solve each system of equations.2x−3y=25x+4y=28

Short Answer

Step by step solution

Step 1. Multiply.

Step 2. Multiply.

Step 3. Subtract.

Step 4. Substitute.

One App. One Place for Learning.

Most popular questions from this chapter

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Use elimination to solve each system of equations.
$2 x - 3 y = 2 5 x + 4 y = 28$