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Chapter 6: Q68. (page 293)

Solve each equation
$\sqrt[3]{x + 5} + 6 = 4$

Short Answer

Expert verified

The solution of the equation is x=-13.

Step by step solution

01

Step 1. Given Information.

Given to solve the equation $\sqrt[3]{x + 5} + 6 = 4$

02

Step 2. Explanation.

Solving the equation by isolating x:

$\begin{array}{l} \sqrt[3]{x + 5} + 6 = 4 \\ \sqrt[3]{x + 5} = 4 - 6 \\ \sqrt[3]{x + 5} = - 2 \\ {(\sqrt[3]{x + 5})}^{3} = {(- 2)}^{3} \\ x + 5 = - 8 \\ x = - 8 - 5 \\ x = - 13 \end{array}$

03

Step 3. Conclusion.

Therefore, the solution of the given equation is x=-13

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Most popular questions from this chapter

Complete parts a-c for each quadratic function.

Find y-intercept, the equation of the axis of symmetry, and the x-coordinate of the vertex.
Make a table of values that includes the vertex.
Use this information to graph the function.

$f (x) = x^{2} + 4$

Simplify

$(4 - 3 i) - (5 - 6 i)$

Complete parts a-c for each quadratic function.

Find y-intercept, the equation of the axis of symmetry, and the x-coordinate of the vertex.
Make a table of values that includes the vertex.
Use this information to graph the function.

$f (x) = x^{2} - \frac{2}{3} x - \frac{8}{9}$

Determine whether each function has a maximum or minimum value. Then find the maximum or minimum value of the function.

$f (x) = x - 2 x^{2} - 1$

Simplify

$i^{14}$

See all solutions

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