Chapter 10: Q58. (page 529)

The number of bacteria in a colony is growing exponentially.
How many bacteria were there at 7 P.M. that day?

Short Answer

Expert verified

The population of bacteria at 7 P.M. that day is1011929.

Step by step solution

Step 1. Given Information.

Given, the number of bacteria in a colony is growing exponentially as below:

An exponential function to model the population y of bacteria x hours after 2 P.M. is $y = 100 {(2 \sqrt{10})}^{x}$

The number of bacteria that were there at 7 P.M. that day is to be determined.

Step 2. Explanation.

For 7 P.M.:

$\begin{array}{l} x = 7 - 2 \\ x = 5 \end{array}$

Plugging the value to in the equation:

$\begin{array}{l} y = 100 {(2 \sqrt{10})}^{x} \\ y = 100 {(2 \sqrt{10})}^{5} \\ y \approx 1011929 \end{array}$

Step 3. Conclusion.

Hence the population of bacteria at 7 P.M. that day is 1011929.

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The number of bacteria in a colony is growing exponentially.
How many bacteria were there at 7 P.M. that day?

Short Answer

Step by step solution

Step 1. Given Information.

Step 2. Explanation.

Step 3. Conclusion.

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The number of bacteria in a colony is growing exponentially.How many bacteria were there at 7 P.M. that day?

Short Answer

Step by step solution

Step 1. Given Information.

Step 2. Explanation.

Step 3. Conclusion.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Mechanics Maths

Probability and Statistics

Statistics

Decision Maths

Discrete Mathematics

Geometry

Study anywhere. Anytime. Across all devices.

The number of bacteria in a colony is growing exponentially.
How many bacteria were there at 7 P.M. that day?