Identify the domain and range of the relation in the graph at the right. Predict the value of $\mathbf{y}$when $\mathbf{x}=\mathbf{5}$.

The x values of the ordered pairs belonging to a relation constitutes the domain of the relation and the y values of the ordered pairs belonging to a relation constitutes the range of the relation.

A line of fit and a prediction equation for a set of data can be found by selecting two points that appear to represent the data well.

The equation of a straight-line passing through the points $\left(h,k\right)$ and $\left(a,b\right)$ is given as $\frac{y-k}{x-h}=\frac{b-k}{a-h}$.

A relation represented by the following graph:

So, the relation is the set of ordered pairs, $\left\{\left(-1,0\right),\left(1,2\right),\left(2,2\right),\left(4,3\right)\right\}$.

The x values of the ordered pairs belonging to the relation $\left\{\left(-1,0\right),\left(1,2\right),\left(2,2\right),\left(4,3\right)\right\}$are $-1,1,2,4$.

So, the domain of the relation is $\left\{-1,1,2,4\right\}$.

The x values of the ordered pairs belonging to the relation $\left\{\left(-1,0\right),\left(1,2\right),\left(2,2\right),\left(4,3\right)\right\}$are $0,2,2,3$.

So, the range of the relation is $\left\{0,2,3\right\}$.

Aside from the point $\left(1,2\right)$, the rest of the points of the relation appears to lie on a straight line. Choosing two of those points, $\left(-1,0\right)$ and $\left(2,2\right)$, the line of fit is given by the straight line passing through these points.

So, $\left(h,k\right)=\left(-1,0\right)$ and $\left(a,b\right)=\left(2,2\right)$.

Put $\left(h,k\right)=\left(-1,0\right)$ and $\left(a,b\right)=\left(2,2\right)$ in $\frac{y-k}{x-h}=\frac{b-k}{a-h}$ to get,

$\frac{y-0}{x-\left(-1\right)}=\frac{2-0}{2-\left(-1\right)}$

$\frac{y}{x+1}=\frac{2}{2+1}$ (Simplify)

$\frac{y}{x+1}=\frac{2}{3}$ (Simplify)

$\frac{y}{x+1}\left(x+1\right)=\frac{2}{3}\left(x+1\right)$ (Multiply both sides by $x+1$)

$y=\frac{2}{3}x+\frac{2}{3}$ (Simplify)

So, $y=\frac{2}{3}x+\frac{2}{3}$ is the prediction equation.

Put $x=5$ in $y=\frac{2}{3}x+\frac{2}{3}$ to get,

So, the predicted value when $x=5$ is $y=4$.