Chapter 4: Q50. (page 174)

Solve each equation.50
$[\begin{matrix} 3 x + 2 \\ 15 \end{matrix}] = [\begin{matrix} 23 \\ - 4 y - 1 \end{matrix}]$

Short Answer

Expert verified

The answer is $(7, - 4)$ that is $x = 7$ and $y = - 4$ .

Step by step solution

- State the definition of a matrix.

A rectangular array of numbers arranged in rows and columns is called a matrix.

- Solve the equation.

Using the definition of equal matices is used to solve the equation.

If the dimension of the matrices are same and corresponding elements are equal then the matrices are equal.

Here the matrices are:

$[\begin{matrix} 3 x + 2 \\ 15 \end{matrix}] = [\begin{matrix} 23 \\ - 4 y - 1 \end{matrix}]$

Since, the matrices are equal then corresponding elements are also equal.

Then, the two linear equations formed are:

$\begin{array}{l} 3 x + 2 = 23 \\ - 4 y - 1 = 15 \end{array}$

Solve the equations to obtain values of x and y .

$\begin{matrix} 3 x + 2 = 23 \\ 3 x + 2 - 2 = 23 - 2 \\ 3 x = 21 \\ x = 7 \end{matrix}$

and $\begin{matrix} - 4 y - 1 = 15 \\ - 4 y - 1 + 1 = 15 + 1 \\ - 4 y = 16 \\ y = - 4 \end{matrix}$

- State the conclusion.

Therefore, $x = 7$ and $y = - 4$ . The solution is $(7, - 4)$

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Solve each equation.50
$[\begin{matrix} 3 x + 2 \\ 15 \end{matrix}] = [\begin{matrix} 23 \\ - 4 y - 1 \end{matrix}]$

Short Answer

Step by step solution

- State the definition of a matrix.

- Solve the equation.

- State the conclusion.

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Solve each equation.50[3x+215]=[23−4y−1]

Short Answer

Step by step solution

- State the definition of a matrix.

- Solve the equation.

- State the conclusion.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Calculus

Mechanics Maths

Discrete Mathematics

Geometry

Applied Mathematics

Statistics

Study anywhere. Anytime. Across all devices.

Solve each equation.50
$[\begin{matrix} 3 x + 2 \\ 15 \end{matrix}] = [\begin{matrix} 23 \\ - 4 y - 1 \end{matrix}]$