Find the x- intercept and the y - intercept of the graph of equation. Then graph the equation.

$5\text{x}-2\text{y}=10$

x - intercept is the point on the graph where a line cuts the x- axis.

Similarly, y- intercept is the point on the graph where a line cuts the y - axis.

Here, the equation is:

$5x-2y=10$ (1)

Now, if a line cuts the x - axis at a point, the coordinate of that point is $(x,0)$since y is always 0 at any point on the x- axis.

Similarly, if a line cuts the y - axis at a point, the coordinate of that point is$(0,y)$ since x is always 0 at any point on the y- axis.

Then, to obtain x- intercept, put $y=0$in equation1, that is:

$\begin{array}{c}5x-2y=10\\ 5x-(2\times 0)=10\\ 5x=10\\ \frac{5x}{5}=\frac{10}{5}\\ x=2\end{array}$

And to obtain y - intercept, put $x=0$in equation1, that is:

$\begin{array}{c}5x-2y=10\\ (5\times 0)-2y=10\\ -2y=10\\ -\frac{2y}{2}=\frac{10}{2}\\ -y=5\\ y=-5\end{array}$

Thus, the x- intercept is $(2,0)$ and y- intercept is $(0,-5)$.

As the x - intercept is $(2,0)$ and y - intercept is $(0,-5)$. Then the graph is:

Therefore, the x - intercept is $(2,0)$ and y- intercept is $(0,-5)$.

And the graph is: