Chapter 4: Q6. (page 171)

Find each product, if possible.
$[\begin{matrix} 3 & - 5 \end{matrix}] \cdot [\begin{matrix} 3 & 5 \\ - 2 & 0 \end{matrix}]$

Short Answer

Expert verified

The required matrix is,

$[\begin{matrix} 19 & 15 \end{matrix}]$

Step by step solution

Step 1- Make the first column of product matrix

Write the multiplication of first element of the row of first matrix and first element of first column of second matrix, after it, do the same with second element.

$[\begin{matrix} 3 \cdot 3 + (- 5) \cdot (- 2) \end{matrix}]$

– Make the second column of product matrix

Write the multiplication of second element of the row of first matrix and first element of second column of second matrix, after it, do the same with second element.

$[\begin{matrix} 3 \cdot 3 + (- 5) \cdot (- 2) & 3 \cdot 5 + (- 5) \cdot 0 \end{matrix}]$

Step 3- Write the actual product matrix

Perform simplification of obtained matrix.

$[\begin{matrix} 19 & 15 \end{matrix}]$

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Find each product, if possible.
$[\begin{matrix} 3 & - 5 \end{matrix}] \cdot [\begin{matrix} 3 & 5 \\ - 2 & 0 \end{matrix}]$

Short Answer

Step by step solution

Step 1- Make the first column of product matrix

– Make the second column of product matrix

Step 3- Write the actual product matrix

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Find each product, if possible.[3−5]⋅[35−20]

Short Answer

Step by step solution

Step 1- Make the first column of product matrix

– Make the second column of product matrix

Step 3- Write the actual product matrix

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Calculus

Pure Maths

Applied Mathematics

Statistics

Mechanics Maths

Geometry

Study anywhere. Anytime. Across all devices.

Find each product, if possible.
$[\begin{matrix} 3 & - 5 \end{matrix}] \cdot [\begin{matrix} 3 & 5 \\ - 2 & 0 \end{matrix}]$