Chapter 4: Q70. (page 188)

Solve the system of equation.
$\begin{array}{l} x + y = - 3 \\ 3 x + 4 y = - 12 \end{array}$

Short Answer

Expert verified

The solution is $x = 0, y = - 3$ .

Step by step solution

Step 1- Consider the equation.

Consider the system of equation

$\begin{array}{l} x + y = - 3 (1) \\ 3 x + 4 y = - 12 (2) \end{array}$

Step 2- Step description.

Multiply the equation (1) by 3 such that $3 x + 3 y = - 9$ . (3)

Subtract the equation (3) from the equation (2) as follows:

$\begin{matrix} 3 x + 4 y - (3 x + 3 y) = - 12 - (- 9) \\ 3 x + 4 y - 3 x - 3 y = - 12 + 9 \\ y = - 3 \end{matrix}$

Step 3- Step description.

Substitute the value of y in equation (1).

$\begin{matrix} x + y = - 3 \\ x + (- 3) = - 3 \\ x - 3 = - 3 \\ x = - 3 + 3 \\ x = 0 \end{matrix}$

Therefore, the solution is $x = 0, y = - 3$ .

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Solve the system of equation.
$\begin{array}{l} x + y = - 3 \\ 3 x + 4 y = - 12 \end{array}$

Short Answer

Step by step solution

Step 1- Consider the equation.

Step 2- Step description.

Step 3- Step description.

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