Chapter 4: Q73. (page 188)

Solve the system of equation.
$\begin{array}{l} 3 x + 5 y = 2 \\ 2 x - y = - 3 \end{array}$

Short Answer

Expert verified

The solution is $x = - 1, y = 1$ .

Step by step solution

Step 1- Consider the equation.

Consider the system of equation

$\begin{array}{l} 3 x + 5 y = 2 (1) \\ 2 x - y = - 3 (2) \end{array}$

Step 2- Step description.

Multiply the equation (2) by 5 such that $10 x - 5 y = - 15$ . (3)

Add the equation (3) and the equation (1) as follows:

$\begin{array}{l} 10 x - 5 y + 3 x + 5 y = - 15 + 2 \\ 13 x = - 13 \\ x = - 1 \end{array}$

Step 3- Step description.

Substitute the value of x in equation (1).

$\begin{array}{l} 3 x + 5 y = 2 \\ 3 (- 1) + 5 y = 2 \\ - 3 + 5 y = 2 \\ 5 y = 2 + 3 \\ y = 1 \end{array}$

Therefore, the solution is $x = - 1, y = 1$ .

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Solve the system of equation.
$\begin{array}{l} 3 x + 5 y = 2 \\ 2 x - y = - 3 \end{array}$

Short Answer

Step by step solution

Step 1- Consider the equation.

Step 2- Step description.

Step 3- Step description.

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Solve the system of equation.3x+5y=22x−y=−3

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Step by step solution

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Step 3- Step description.

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Solve the system of equation.
$\begin{array}{l} 3 x + 5 y = 2 \\ 2 x - y = - 3 \end{array}$