Chapter 4: Q74. (page 188)

Solve the system of equation.
$\begin{array}{l} 6 x + 2 y = 22 \\ 3 x + 7 y = 41 \end{array}$

Short Answer

Expert verified

The solution is $x = 2, y = 5$ .

Step by step solution

Step 1- Consider the equation.

Consider the system of equation

$\begin{array}{l} 6 x + 2 y = 22 (1) \\ 3 x + 7 y = 41 (2) \end{array}$

Step 2- Step description.

Multiply the equation (2) by 2 such that $6 x + 14 y = 82$ . (3)

Subtract the equation (1) from the equation (3) as follows:

$\begin{array}{l} 6 x + 14 y - (6 x + 2 y) = 82 - 22 \\ 6 x + 14 y - 6 x - 2 y = 60 \\ 12 y = 60 \\ y = 5 \end{array}$

Step 3- Step description.

Substitute the value of x in equation (1).

$\begin{array}{l} 6 x + 2 y = 22 \\ 6 x + 2 (5) = 22 \\ 6 x + 10 = 22 \\ 6 x = 12 \\ x = 2 \end{array}$

Therefore, the solution is $x = 2, y = 5$ .

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Solve the system of equation.
$\begin{array}{l} 6 x + 2 y = 22 \\ 3 x + 7 y = 41 \end{array}$

Short Answer

Step by step solution

Step 1- Consider the equation.

Step 2- Step description.

Step 3- Step description.

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Solve the system of equation.6x+2y=223x+7y=41

Short Answer

Step by step solution

Step 1- Consider the equation.

Step 2- Step description.

Step 3- Step description.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Geometry

Probability and Statistics

Applied Mathematics

Theoretical and Mathematical Physics

Pure Maths

Logic and Functions

Study anywhere. Anytime. Across all devices.

Solve the system of equation.
$\begin{array}{l} 6 x + 2 y = 22 \\ 3 x + 7 y = 41 \end{array}$