Chapter 1: Q45. (page 38)

Define a variable and write an inequality for each problem and then solve.
45. Twice the sum of a number and 5 is no more than 3 times that same number increased by 11.

Short Answer

Expert verified

The inequality is: $2 (x + 5) \leq 3 x + 11$

Value of the number is $x \geq - 1$

Step by step solution

- Define the variable.

A variable is a term that is used to represent an unknown value.

- Write the inequality.

From given, let the number added to 5 be $x$ .

As twice the sum is no more than 3 times $x$ increased by 11.

So, the inequality is:

$2 (x + 5) \leq 3 x + 11$

- Solve the inequality.

To simplify this inequality, use subtraction property

\begin{matrix} 2 (x + 5) \leq 3 x + 11 \\ 2 x + 10 \leq 3 x + 11 \\ 10 - 11 \leq 3 x - 2 x \\ x \geq - 1 \end{matrix}

Therefore, the inequality is $2 (x + 5) \leq 3 x + 11$ and the value of $x$ is $x \geq - 1$ .

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Define a variable and write an inequality for each problem and then solve.
45. Twice the sum of a number and 5 is no more than 3 times that same number increased by 11.

Short Answer

Step by step solution

- Define the variable.

- Write the inequality.

- Solve the inequality.

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Define a variable and write an inequality for each problem and then solve.45. Twice the sum of a number and 5 is no more than 3 times that same number increased by 11.

Short Answer

Step by step solution

- Define the variable.

- Write the inequality.

- Solve the inequality.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Applied Mathematics

Logic and Functions

Discrete Mathematics

Calculus

Pure Maths

Statistics

Study anywhere. Anytime. Across all devices.

Define a variable and write an inequality for each problem and then solve.
45. Twice the sum of a number and 5 is no more than 3 times that same number increased by 11.