Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 1: Q67. (page 46)

Solve each equation. Check your solutions.

67. 8c+7=-4

Short Answer

Expert verified

The solution set of given equation is ∅.

Step by step solution

01

– Description of step.

For any real numbers p and q, where q≥0,

Case 1) if p=q then p=q or

Case 2) ifp=q then p=-q

02

– Description of step.

The given equation is 8c+7=-4. This statement is not true since, the absolute value of a real number is non-negative irrespective of its sign.

03

– Description of step.

The statement 8c+7=-4is not true and hence the solution is ∅.

Therefore, the solution set of given equation is ∅.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Name the property illustrated by each equation.

31. 5+-2+-4=5+-2+-4

Name the sets of numbers to which all of the following numbers belong. Then arrange the numbers in order from least to greatest.

2.49¯,2.49¯,2.4,2.49,2.9¯

Find the value of each expression

28.134-72

Evaluate each expression x=4,y=−2,if and z=6

x+3y+z−y

Evaluate each expression if w=6,x=0.4,y=12,andz=-3

43.5x+2z
See all solutions

Recommended explanations on Math Textbooks

Pure Maths

Read Explanation

Applied Mathematics

Read Explanation

Probability and Statistics

Read Explanation

Theoretical and Mathematical Physics

Read Explanation

Geometry

Read Explanation

Calculus

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free