Determine whether the given point satisfies each inequality.

$4x-2y>6; \left(3,3\right)$

A linear inequality is like a linear equation but with an inequality sign instead of equal to sign. For example, $x+y\le 3$ is a linear inequality and $x+y=3$ is the related linear equation.

A point that satisfies the inequality makes the inequality true otherwise inequality will be false.

The steps to graph the inequality are provided below.

1. If the inequality contains greater than or less than sign then the boundary of the line will be dashed. If the inequality contains signs of greater than or equal to or less than or equal to then the boundary of the line will be solid.

2. Select a point (known as test point) from the plane that does not lie on the boundary on the line and substitute it in the inequality.

3. If the inequality is true then shade the region that contains the test point otherwise shade the other region when inequality is false.

Consider the inequality provided below.

$4x-2y>6$

The inequality contains the greater than sign.

Therefore, the boundary line will be dotted.

The corresponding equation is $4x-2y>6$and the given point is $\left(3,3\right)$.

Substitute $x=3$and $y=3$and check whether the inequality is true or false.

$\begin{array}{c}4x-2y>6\\ 4\left(3\right)-2\left(3\right)>6\\ 12-6>6\\ 6>6\end{array}$

This is false.

Thus, the given point does not satisfies the given inequality.

Graphical representation

The shaded region represents all the points that will satisfy the inequality and the given point does not lie in the shaded region.

Hence, the point $\left(3,3\right)$ does not satisfy the inequality $4x-2y>6$.