Solve each system of equations.

7.

2r+3s4t=204rs+5t=133r+2s+4t=15

Short Answer

Expert verified

The solution is r=5,s=-2,t=-1.

Step by step solution

01

Step-1 –Using elimination to obtain two equations with two variables

Given system of equations are

2r+3s4t=204rs+5t=133r+2s+4t=15

Multiplying second equation by 3and adding to the first equation, we get

2r+12r4t+15t=20+3914r+11t=59

Again multiplying second equation by 2and adding to the third equation, we get

8r+3r+10t+4t=26+1511r+14t=41

02

Step-2 –Solving the system of two equations with two variables

System of two equations with two variables are

114r+11t=5911r+14t=41

Multiplying the first equation by11and second by 14and subtracting them we get

121t-196t=649-574-75t=75t=-1

Putting the value of tin equation 14r+11t=59we get

14r11=5914r=59+1114r=70r=5

03

Step-3 –Finding the value of s using the value of r and t

Putting the value of r andtin the equation \[4r-s+5t\]\[4r-s+5t\]we get,

4(5)s+5(1)=1320s5=13s=1315s=2s2

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