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Chapter 14: Q45. (page 768)

Solve the equation $x = \sin^{- 1} (1)$ .

Short Answer

Expert verified

The solution for the equation is $x = \frac{π}{2}$ .

Step by step solution

Step 1. Write down the given equation.

The given equation is $x = \sin^{- 1} (1)$ .

Step 2. Simplify the equation.

The given equation $x = \sin^{- 1} (1)$ is solved as:

$\begin{matrix} x = \sin^{- 1} (1) .... (Given) \\ \sin x = 1 \\ x = \frac{π}{2} \end{matrix}$

Step 3. Conclusion.

The solution for the given equation is $x = \frac{π}{2}$ .

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Most popular questions from this chapter

Identify the equation of the graphed function.

$\begin{matrix} (A) y = \frac{1}{2} \sin (4 θ) \\ (B) y = 2 \sin (\frac{1}{4} θ) \\ (C) y = \frac{1}{4} \sin (2 θ) \\ (D) y = 4 \sin (\frac{1}{2} θ) \end{matrix}$

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Find the amplitude if it exists and period of the function $y = 2 \sin (θ)$ and then graph the function.

State the vertical shift, amplitude, period and phase shift of the function $y = 4 \cos [2 (θ + 30 °)] - 5$ and then graph the function.

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Solve the equation x=sin-11.

Short Answer

Step by step solution

Step 1. Write down the given equation.

Step 2. Simplify the equation.

Step 3. Conclusion.

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Solve the equation $x = \sin^{- 1} (1)$ .