Chapter 6: Q. 16 (page 510)

For each pair of definite integrals in exercise 13-18 decide which if either is larger without computing the integrals
$π \int_{0}^{3} x^{2} d x a n d π \int_{0}^{3} (9 - x^{2}) d x$

Short Answer

Expert verified

The integral $π \int_{0}^{3} (9 - x^{2}) d x$ is bigger

Step by step solution

Given information

We are given two integrals

$π \int_{0}^{3} x^{2} d x a n d π \int_{0}^{3} (9 - x^{2}) d x$

Explaination

The term $x^{2} i s b i g g e r 9 - x^{2} o n i n t e g r a t i n g$

And after substituting the limits in the integrated value the second term will be 9 more than that of the first term.

Hence the second term is bigger

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For each pair of definite integrals in exercise 13-18 decide which if either is larger without computing the integrals
$π \int_{0}^{3} x^{2} d x a n d π \int_{0}^{3} (9 - x^{2}) d x$

Short Answer

Step by step solution

Given information

Explaination

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For each pair of definite integrals in exercise 13-18 decide which if either is larger without computing the integralsπ∫03x2dxandπ∫03(9-x2)dx

Short Answer

Step by step solution

Given information

Explaination

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Most popular questions from this chapter

Recommended explanations on Math Textbooks

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Study anywhere. Anytime. Across all devices.

For each pair of definite integrals in exercise 13-18 decide which if either is larger without computing the integrals
$π \int_{0}^{3} x^{2} d x a n d π \int_{0}^{3} (9 - x^{2}) d x$