For each function f that follows, construct sign charts forf, f',and f '', if possible. Examine function values or limits at any interesting values and at ±∞. Then interpret this information to sketch a labeled graph of f.

f(x)=xex.

Short Answer

Expert verified

Sign charts forf, f',and f ''are the following.

Graph of function is following.

Step by step solution

01

Step 1. Given information. 

The given function isf(x)=xex.

02

Step 2. Roots of the function. 

Equate the function to zero.

f(x)=0xex=0x=0

the function root of the function isx=0.

03

Step 3. critical points of the function. 

Determine the first derivative of the function.

f'(x)=ddxxex=(x+1)ex

critical points of the function.

f'(x)=0(x+1)ex=0x+1=0x=-1

so the function has critical point atx=-1.

04

Step 4. inflection point of the function. 

find the second derivative of the function.

f''(x)=ddx(x+1)ex=(x+2)ex

Roots of the second derivative of the function.

f''(x)=0(x+2)ex=0x+2=0x=-2

So the function has an inflection point at x=-2.

So the sign chart is the following.

05

Step 5. Graph of function. 

The graph of the function is the following.

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