For each graph of f in Exercises 37–40, explain why f satisfies the hypotheses of Rolle’s Theorem on the given interval [a, b]. Then approximate any values c ∈ (a, b) that satisfy the conclusion of Rolle’s Theorem.

[a, b] = [−3, 1]

Short Answer

Expert verified

The hypotheses of Rolle's theorem is satisfied because the graph of f appears to be continuous on -3,1and differentiable on -3,1. The values of cthat satisfies the conclusion of Rolle's theorem arec-2.3,c=-1,c0.3

Step by step solution

01

Step 1. Given information.

Consider the graph of f for the interval -3,1.

02

Step 2. Satisfy hypothesis of Rolle's theorem.

It can be observed that the given graph has no break, hole or gap in the interval -3,1. So, the graph of f appears to be continuous on -3,1.

It can be observed that the graph has no corner, no vertical line or no discontinuous point in the interval -3,1. So, the graph of f appears to be differentiable on -3,1.

Thus, the hypothesis of Rolle's theorem is satisfied.

03

Step 3. Find values of c.

From the graph, f-3=0and f1=0.

f-3=f1

So, Rolle's theorem applies then there exists somec-3,1 such thatf'c=0 or the graph has horizontal tangent line.

From the graph, such values of c where the graph has horizontal tangent line are c-2.3,c=-1,c0.3.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free