Use the first derivative test to determine the local extrema of each function in Exercises 39- 50. Then verify your algebraic answers with graphs from a calculator or graphing utility.

f(x)=x2(x-1)(x+1)

Short Answer

Expert verified

Ans: The local extrema value of f(x) are

Max at x=0

Min at x=±12

Step by step solution

01

Step 1. Given Information

f(x)=x2(x-1)(x+1)

02

Step 2. Finding the derivative of the function

Rewriting the function by simplifying it,

f(x)=x2(x-1)(x+1)=x2(x2-1)=x4-x2f'(x)=4x3-2xlet,f'(x)=04x3-2x=02x(2x2-1)=02x=0x=02x2-1=02x2=1x=±12x=0,±12

03

Step 3. Substituting the values into the function equation:

x=-2,12,2intothef'(x)=x4-x2f'(-2)=(-2)4-(-2)2=12>0f'(2)=(2)4-(2)2=12>0f'(12)=(12)4-(12)2=-316<0

04

Step 4. Finding local extrema of the function on the number line(Sign chart): 

05

Step 5. Verifying algebraic answers with graphs :

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