Use a sign chart for f''to determine the intervals on which each function f in Exercises 41–52 is concave up or concave down, and identify the locations of any inflection points. Then verify your algebraic answers with graphs from a calculator or graphing utility

f(x)=(x-3)3(x-1)

Short Answer

Expert verified

The function is concave up on both (-,2),(3,) and concave down on(2,3).

Step by step solution

01

Step 1. Given Information.

The given function isf(x)=(x-3)3(x-1)

02

Step 2. Second derivative.

On differentiating, we get,

f'(x)=ddx(x-3)3(x-1)=ddx(x-3)3(x-1)+(x-3)3ddx(x-1)=3(x-3)2(x-1)+(x-3)3=2(x-3)2(2x-3)f''(x)=ddx2(x-3)2(2x-3)=2ddx(x-3)2(2x-3)=22(x-3)(2x-3)+2(x-3)2=12(x-3)(x-2)

03

Step 3. Sign chart.

Now,

f''(x)=0whenx=2andx=3,.

Therefore, the sign chart will be,

The function has inflexion points x=2,3.

Thefunctionis concave up on both(-,2),(3,)and concave down on(2,3)

04

Step 4. Verification.

The graph of the function is,

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