Use the first derivative test to determine the local extrema of each function in Exercises 39- 50. Then verify your algebraic answers with graphs from a calculator or graphing utility.

f(x)=(x-1)2x+2

Short Answer

Expert verified

Ans: The local minimum of the function f(x) is at x=1

The local maximum of the function f(x) is at x=-5

Step by step solution

01

Step 1. Given Information:

f(x)=(x-1)2x+2

02

Step 2. Finding the derivative of the function

Rewriting the function by simplifying it,

f(x)=(x-1)2x+2f'(x)=(x+2)2(x-1)-1-(x-1)2-1(x+2)2f'(x)=(x+2)(2x-2)-x2-2x+1(x+2)2f'(x)=2x2-2x+4x-4-x2+2x-1(x+2)2f'(x)=x2+4x-5(x+2)2let,f'(x)=0x2+4x-5(x+2)2=0x2+4x-5=0x2+5x-x-5=0x(x+5)-(x+5)=0(x+5)(x-1)=0so,theciticalpointsarex=-5,1

03

Step 3. Substituting the values into the function equation:

f(-5)=(-5-1)2-5+2=(-6)2-3=36-3=-12<0f(1)=(1-1)21+2=(0)23=0=0thelocalminimumatx=1:andlocalmaximumatx=-5

04

Step 4. Verifying algebraic answers with graphs : 

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