Use a sign chart for f''to determine the intervals on which each function f in Exercises 41–52 is concave up or concave down, and identify the locations of any inflection points. Then verify your algebraic answers with graphs from a calculator or graphing utility

f(x)=2x1-2x

Short Answer

Expert verified

There is no Inflection point . The function is concave up on(-,0)and concave down on(0,).

Step by step solution

01

Step 1. Given information.

The given function isf(x)=2x1-2x.

02

Step 2. Second Derivative.

On differentiating the function, we get,

f'(x)=ddx2x1-2x=2xln21-2x-2xddx1-ddx2x1-2x2=2xln22x-12f''(x)=ddx2xln22x-12=-ln2(2)2x2x+12x-13

03

Step 3. Sign chart.

Now,

f''(x)=0atx=0.

Therefore,

the sign chart will be,

The function isconcave up on(-,0)and concave down on(0,)and no inflection point as domain is(-,0)(0,).

04

Step 4. Verification.

The graph of the function is,

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