Use a sign chart forf'' to determine the intervals on which each function f in Exercises 41–52 is concave up or concave down, and identify the locations of any inflection points. Then verify your algebraic answers with graphs from a calculator or graphing utility

f(x)=3cosπ2x+5

Short Answer

Expert verified

Inflection points arex=1+4n,3+4n,concave up on(1+4n,3+4n)and concave down on(4n,1+4n),(3+4n,4+4n).

Step by step solution

01

Sep 1. Given information.

The given function isf(x)=3cosπ2x+5.

02

Step 2. Second derivative.

On differentiating, we get,

f'(x)=ddx3cosπ2x+5=-3π2sinπ2xf''(x)=ddx-3π2sinπ2x=-3π24cosπ2x

03

Step 3. Sign chart.

Now,

f''(x)=0atx=1+4n,3+4n.

Inflection points: x=1+4n,3+4n.

Concave up: (1+4n,3+4n)

Concave down:(4n,1+4n),(3+4n,4+4n)

04

Step 4. Verification.

The graph of the function is :

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