Find a function f that has the given derivative f' and value f(c), if possible.

f'(x)=x8x2+1,f(0)=1

Short Answer

Expert verified

The function is thisx99-x33+x+c

and value of f(-1)=-209

Step by step solution

01

Step 1.Given

The given function isf'(x)=x8x2+1,f(0)=1

02

Step 2. Finding the function using integration

Integratingbothsideswithrespecttox,f'(x)=x8x2+1dx=x99-x33+x+cwherecisconstant

03

Step 3. Finding the value of f(c).

whenf(0)=-1f(x)=x99-x33+x+cf(0)=0-0+0+c-1=cf(c)=f(-1)=(-1)99-(-1)33+(-1)+-1=19-13-1-1=-29-2=-209

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