Functions defined by area accumulation: We know that for fixed real numbers a and b and an integrable functionf, the definite integral abf(x)dxis a real number. For different real values of b, we get (potentially) different values for the integral abf(x)dx.

Now make a table of the values of the integral 1b2xdxcorresponding to the values -3,-2,-1,0,1,2,and3for b. Conjecture a formula for the relationship between the values of b and the corresponding value of the integral.

Short Answer

Expert verified

The formula for the integral is 1b2xdx=b2-1and the table of values of integral for different values of b is following.

Step by step solution

01

 Step 1. Given information.   

The given integral isabf(x)dx=1b2xdx.

Given values of b are-3,-2,-1,0,1,2,and3.

02

Step 2. Integral of ∫1b2x dx.

Determine the integral of 1b2xdx.

role="math" localid="1648629234589" abf(x)dx=1b2xdx=21bxdx=2x221b=2b22-122=b2-1

So1b2xdx=b2-1.

03

Step 2. Values of integral. 

Substitute -3,-2,-1,0,1,2,and3for bin the integral.

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