Chapter 4: Q. 40 (page 353)

If $\int_{- 2}^{3} f (x) d x = 4, \int_{- 2}^{6} f (x) d x = 9, \int_{- 2}^{3} g (x) d x = 2$ , and $\int_{3}^{6} g (x) d x = 3$ , then find the values of each definite integral in Exercises $29 - 40$ . If there is not enough information, explain why.
$\int_{- 2}^{- 2} x (f (x) + 3)^{2} d x$

Short Answer

Expert verified

The value of definite integral cannot be found as there is not enough information.

Step by step solution

Step 1. Given Information

We are given,

$\int_{- 2}^{- 2} x (f (x) + 3)^{2} d x$

Step 2. Finding the Integral

The definite integral cannot be found out as there is not enough information available. Therefore, the value is not possible to find.

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If $\int_{- 2}^{3} f (x) d x = 4, \int_{- 2}^{6} f (x) d x = 9, \int_{- 2}^{3} g (x) d x = 2$ , and $\int_{3}^{6} g (x) d x = 3$ , then find the values of each definite integral in Exercises $29 - 40$ . If there is not enough information, explain why.
$\int_{- 2}^{- 2} x (f (x) + 3)^{2} d x$

Short Answer

Step by step solution

Step 1. Given Information

Step 2. Finding the Integral

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If ∫-23f(x)dx=4,∫-26f(x)dx=9,∫-23g(x)dx=2, and ∫36g(x)dx=3, then find the values of each definite integral in Exercises 29-40. If there is not enough information, explain why.∫-2-2x(f(x)+3)2dx

Short Answer

Step by step solution

Step 1. Given Information

Step 2. Finding the Integral

One App. One Place for Learning.

Most popular questions from this chapter

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Theoretical and Mathematical Physics

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Study anywhere. Anytime. Across all devices.

If $\int_{- 2}^{3} f (x) d x = 4, \int_{- 2}^{6} f (x) d x = 9, \int_{- 2}^{3} g (x) d x = 2$ , and $\int_{3}^{6} g (x) d x = 3$ , then find the values of each definite integral in Exercises $29 - 40$ . If there is not enough information, explain why.
$\int_{- 2}^{- 2} x (f (x) + 3)^{2} d x$