Chapter 2: Q. 12 (page 197)

Given that f,g,h are functions with values f(2)=1, g(2)=-4, h(2)=3 and point -derivatives f'(2)=3, g'(2)=0, h'(2)=-1 Calculate
$(2 f + 3 g - h)' (2)$

Short Answer

Expert verified

Hence the value is $(2 f + 3 g - h)' (2) = 7$

Step by step solution

Given information

We are given that f,g,h are functions with values f(2)=1, g(2)=-4, h(2)=3 and point -derivatives f'(2)=3, g'(2)=0, h'(2)=-1

Compute the derivative

We are given $(2 f + 3 g - h)' (2)$

Which can be simplified as

$2 f' (2) + 3 g' (2) - h' (2) 2 (3) + 3 (0) + 1 6 + 1 = 7$

hence $(2 f + 3 g - h)' (2) = 7$

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Given that f,g,h are functions with values f(2)=1, g(2)=-4, h(2)=3 and point -derivatives f'(2)=3, g'(2)=0, h'(2)=-1 Calculate
$(2 f + 3 g - h)' (2)$

Short Answer

Step by step solution

Given information

Compute the derivative

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Given that f,g,h are functions with values f(2)=1, g(2)=-4, h(2)=3 and point -derivatives f'(2)=3, g'(2)=0, h'(2)=-1 Calculate(2f+3g-h)'(2)

Short Answer

Step by step solution

Given information

Compute the derivative

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Mechanics Maths

Statistics

Theoretical and Mathematical Physics

Decision Maths

Calculus

Logic and Functions

Study anywhere. Anytime. Across all devices.

Given that f,g,h are functions with values f(2)=1, g(2)=-4, h(2)=3 and point -derivatives f'(2)=3, g'(2)=0, h'(2)=-1 Calculate
$(2 f + 3 g - h)' (2)$