Use logarithmic differentiation to find derivative

(sinx)x

Short Answer

Expert verified

The derivative of given function is

f(x)=ln(sinx)+xcosxsinx(sinx)x

Step by step solution

01

Step 1. Given information

We have been given

f(x)=(sinx)x

to find the derivative of this function .

02

Step 2.Finding derivative 

Product rule for differentiation

(fg)(x)=f(x)g(x)+f(x)g(x)

Quotient rule for differentiation

fg(x)=f(x)g(x)f(x)g(x)(g(x))2

Now ,

ddx(sinhx)=coshxddx(coshx)=sinhxddx(tanhx)=sech2xddxsinh1x=1x2+1ddxcosh1x=1x21ddxtanh1x=11x2

03

Step 3.Using log to get derivative 

f(x)=(sinx)xlnf(x)=ln(sinx)x[Taking log in both sides]lnf(x)=xln(sinx)f(x)f(x)=ddx(xln(sinx))Differentiate both sideswith respect toxf(x)f(x)=ddx(x)ln(sinx)+xddxln(sinx)=ln(sinx)+xsinxddxsinxUsing product ruleUsing chain ruleddxlnx=1x=ln(sinx)+xsinx(cosx)ddxsinx=cosxf(x)=ln(sinx)+xcosxsinxf(x)[Multiplying both sides byf(x)]f(x)=ln(sinx)+xcosxsinx(sinx)x

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