Prove that if a function fis differentiable at x=c, then f is continuous at x=c.

(a) We are given that f is differentiable at x=c. Use the alternative definition of the derivative to write down what that statement means.

(b) We want to show that f is continuous at x=c. Use the definition of continuity to show that this statement is equivalent to the statement limxc(f(x)f(c))=0.

(c) Now use part (a) to show that limxc(f(x)f(c))=0.

(Hint: Multiply ( f(x)f(c)byxcxcand use the product rule for limits.)

Short Answer

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Ans:

Part (a).limxcf(x)-f(c)x-c=f(c)itiscontinuousatx=c

Part (b).limxc-f(x)=limxc+f(x)=f(c)

Part (c).limxc[f(x)-f(c)]=0

Step by step solution

01

Step 1. Given information:

function fis differentiable atx=c

02

Step 2. Solving Part (a):

Since fis differentiable at x=c

limxcf(x)-f(c)x-c=f'(c)limxcf(x)-f(c)limxcx-c=f'(c)usingdivisionrulelimxcf(x)-f(c)=f'(c)[limxcx-c]limxcf(x)-limxcf(c)=f'(c)·0limxcf(x)=f(c)Henceitiscontinuousatx=c

03

Step 3. Solving Part (b): 

A function is said to be continuous at limxc-f(x)=limxc+f(x)=f(c)

The limit of the function exists at x=c

limxcf(x)=f(c)limxcf(x)=limxcf(c)limxcf(x)-limxcf(c)=0limxcf(x)-f(c)=0Hencebothstatementsareequivalent

04

Step 4. Solving Part (c): 

limxc[f(x)-f(c)]=limxc[f(x)-f(c)]x-cx-c=limxc[f(x)-f(c)]x-c·limxc(x-c)=f'(c)·limxc(x-c)=f'(c)·(c-c)limxc[f(x)-f(c)]=0

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