Evaluate each of the double integrals in Exercises 37-54as iterated integrals.

Rx2exydA,

whereR=x,y|0x1and0y1.

Short Answer

Expert verified

The value of double integral is :-

Rx2exydA=12

whereR=x,y|0x1and0y1

Step by step solution

01

Step 1. Given Information

We have given the following double integral :-

Rx2exydA,

whereR=x,y|0x1and0y1

We have to evaluate this double integral.

02

Step 2. Use iterated integrals 

The given double integral is :-

Rx2exydA,

where R=x,y|0x1and0y1

In order to solve this double integral we will firstly integrated withy.

Then by using Fubini's Theorem, we can writ this double integral as following :-

role="math" localid="1650586863367" Rx2exydA=0101Rx2exydydx

Then by using iterated integrals, we have :-

0101Rx2exydydx=0101Rx2exydydx

Now we can solve this integral as following :-

0101Rx2exydydx=01x2exyx10dx=01x2xex-e0dx=01xex-1dx=01xex-xdx

Now use product rule of integration fxgxdx=fxgxdx-ddxfxgxdxdx

=xex-ex-x2210=e-e-12-0-e0-0=-12+1=12

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