Prove Theorem 13.10 (a). That is, show that if f(x,y)is an integrable function on the general region and c∈R, then

∬Ωαf(x,y)dA=α∬Ωf(x,y)dA

Short Answer

Expert verified

To prove this, write the double integral on left hand side as double Reimann sum.

Step by step solution

01

Given Information

It is given that

∬Ωcf(x,y)dA=c∬Ωf(x,y)dA

Region is subset of rectangular region defined by

role="math" localid="1653943372914" R={(x,y)∣a≤x≤bandc≤y≤d}, that is,Ω⊆Randc is real number.

02

Simplify using property

We know property of double integral

∬Ωf(x,y)dA=∬RF(x,y)dA

and

localid="1653944299120" F(x,y)=(x,y),if(x,y)∈Ωand 0,if(x,y)∉Ω

write the double integral on left hand side as double Reimann sum.

∬RcF(x,y)dA=limΔ→0∑i=1m∑j=1ncFxi*,yj*ΔAand

Δ=(Δx)2+(Δy)2

Simplify RHS

∬RcF(x,y)dA=climΔ→0∑i=1m∑j=1nFxi*,yj*ΔA

=c∬RF(x,y)dA

From same property ∬Ωcf(x,y)dA=c∬Ωf(x,y)dA

Equation is true.

03

Simplification

Changing order of sum

∬RcF(x,y)dA=limΔ→0∑j=1n∑i=1mcFxi*,yj*ΔA

∬RcF(x,y)dA=climΔ→0∑j=1n∑i=1mFxi*,yj*ΔA

=c∬RF(x,y)dA

From property stated above

∬Ωcf(x,y)dA=c∬Ωf(x,y)dA

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