Interesting trigonometric limits: For each of the functions that follow, use a calculator or other graphing utility to examine the graph of f near x = 0. Does it appear that f is continuous at x = 0? Make sure your calculator is set to radian mode

f(x)=1xsin(x),ifx01,ifx=0

Short Answer

Expert verified

Function is continuous at the given point.

Step by step solution

01

Step 1. Given information

We have to explain that f is continuous at x=0

02

Step 2. Explanation

Put x=0

f(0)=1

limxaf(x)=f(a)limxa+f(x)=f(a)

Left continuity

role="math" localid="1649854552566" limxa-f(x)=f(a)

Right continuity

limxa+f(x)=f(a)limx0f(x)=limx0xsin1x

Dividing and multiplying by1x

03

Step 3. Solving for right continuity

limx0f(x)=limx0xxsin1x1xlimx0f(x)=limx01limx0f(x)=1limx0+f(x)=limx0+xsin1x

Dividing and multiplying by 1x

limx0+f(x)=limx0+xxsin1x1xlimx0+f(x)=limx0+1limx0+f(x)=1limxaf(x)=limxa+f(x)=f(a)

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