In Exercises 39–44, use Theorem 1.16 and left and right limits to determine whether each function f is continuous at its break point(s). For each discontinuity of f, describe the type of discontinuity and any one-sided discontinuity.

f(x)=(x-3),ifx<3-(x-3),ifx3.

Short Answer

Expert verified

Thegivenfunctioniscontinuousatallpointsinitsdomainanditisbothleftandrightcontinuousatx=3.

Step by step solution

01

Step 1. Given Information. 

Given the function:

f(x)=(x-3),ifx<3-(x-3),ifx3andithasit'sbreakpointatx=3.

02

Step 2. Finding the limits at the break point. 

Atx=3,LHL=limx3-f(x)=limx3-(x-3)=(3-3)=0.RHL=limx3+f(x)=limx3+-(x-3)=-(3-3)=0.f(3)=-(3-3)=0.So,LHL=RHL=f(3).

03

Step 3. Finding the type of discontinuity.

Since the function is not discontinuous anywhere so no question arises for the type of discontinuity and as it is continuous all over in its domain therefore, it is both left continuous and right continuous at x=3.

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