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Chapter 1: Q.62 (page 136)

Calculate each of the limits:
$\lim_{x \to 0} \frac{1}{s e c^{- 1} x}$ .

Short Answer

Expert verified

The solution for the limit $\lim_{x \to 0} \frac{1}{s e c^{- 1} x}$ is, $\frac{1}{s e c^{- 1} 0}$ .

Step by step solution

01

Step 1. Given Information.

The limit is,

$\lim_{x \to 0} \frac{1}{s e c^{- 1} x}$ .

02

Step 2. Finding the solution.

$\lim_{x \to 0} \frac{1}{s e c^{- 1} x}$

Inputting $x = 0$ ,

$= \frac{1}{s e c^{- 1} (0)}$

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Most popular questions from this chapter

$\lim_{x \to + 2} \sqrt{2^{x} - 4}$

Write delta-epsilon proofs for each of the limit statements $\lim_{x \to c} f (x) = L$ in Exercises $47 - 60$ .

$\lim_{x \to 4} (6 x - 1) = 23$ .

Write a delta–epsilon proof that proves that $f$ is continuous on its domain. In each case, you will need to assume that δ is less than or equal to $1$ .

$f (x) = x^{2}$

$\lim_{x \to 1} (\frac{e^{x} - 1}{e^{2 x} + 2 e^{x} - 3})$

State what it means for a function f to be left continuous at a point x = c, in terms of the delta–epsilon definition of limit.

See all solutions

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