Continuity: Find the set of points where the function is continuous.

f(x,y,z)=x+y+zx2y+3z

Short Answer

Expert verified

The given function is continuous for all (x, y, z) inR3at all points except those where x-2y+3z=0

Step by step solution

01

Step 1. Given information

f(x,y,z)=x+y+zx2y+3z

02

Step 2. Explanation

The given function f(x,y,z)=x+y+zx2y+3zis a rational function.

Therefore, f(x, y, z) is continuous for all (x, y, z) in R3at all points except those where x-2y+3z=0

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