Use the definition of the partial derivative to find the partial derivatives specified in Exercises 23–26.

fx,fyandfzwhenfx,y,z=xy2z

Short Answer

Expert verified

Required partial derivatives are:fx=y2z,fy=2xyxandfz=-xy2z2

Step by step solution

01

Given 

The given function is:fx,y,z=xy2z.

02

To find

We have to findfx,fyandfz.

03

Calculation 

Differentiate both sides with respect to x, y, and z respectively.

fx,y,z=xy2zfx=xxy2zfx=y2zfx,y,z=xy2zfy=yxy2zfy=2xyxfx,y,z=xy2zfz=zxy2zfz=zxy2z-1fz=xy2-1z-2fz=-xy2z2Hence,fx=y2z,fy=2xyxandfz=-xy2z2

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