Find the first-order partial derivatives for the functions in Exercises 27–36.

fx,y,z=xy2x+z

Short Answer

Expert verified

The first-order partial derivatives arefx=zy2x+z2,fy=2xyx+z,fz=-xy2x+z2.

Step by step solution

01

Given 

The given function is: fx,y,z=xy2x+z

02

To find  

We have to find the first-order partial derivatives.

03

Calculation 

fx,y,z=xy2x+zfx=xxy2x+z-xy2xx+zx+z2fx=y2x+z-xy21x+z2fx=xy2+zy2-xy2x+z2fx=zy2x+z2fx,y,z=xy2x+zfy=yxy2x+zfy=2xyx+zfx,y,z=xy2x+zfz=zxy2x+zfz=-xy2x+z2zx+zfz=-xy2x+z21fz=-xy2x+z2Hence,fx=zy2x+z2,fy=2xyx+z,fz=-xy2x+z2.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.

Sign-up for free