complete Example 4 by evaluating the integral

02π2+2cosθdθ

Short Answer

Expert verified

The required answer is8

Step by step solution

01

Given information

The integral is 02π2+2cosθdθ

02

The objective is to find the value of the integral.

The integral02π2+2cosθdθ.

02π2+2cosθdθ=02π2(1+cosθ)dθ=202π(1+cosθ)dθ

Then,

02π2+2cosθdθ=202π(1+2cos2θ2-1)dθsincecosθ=2cos2θ2-1=202π2cos2θ2dθ=202π2cosθ2dθ

03

Find the value of integral

In this case, the supplied function has a negative value in the interval πto 2π

Calculate the integral in the range of 0to πand multiply it by 2

02π2+2cosθdθ=22(2sinθ2)0π=8(sinπ2-0)02π2+2cosθdθ=8

Hence, the value of the integral is8

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