Use Cartesian coordinates to express the equations for the parabolas determined by the conditions specified in Exercises 22–31.

directrixx=x0, focusx1,y1,wherex0x1.

Short Answer

Expert verified

The equation isy1-y2=-2xx0-x1+x02-x12.

Step by step solution

01

Step 1. Given information.

The given values are:

directrixx=x0, focusx1,y1,wherex0x1

02

Step 2. Distance formula.

Let any point on the parabola be (x,y)

Co-ordinates of the focus is (x1,y1)

The distance between the point and the focus is,

Distance=x1-x2+y1-y2sincex1=x,y1=y,x2=x1,y2=y1Now the distance between the point and the directrix isx-x0.Therefore,x1-x2+y1-y2=x-x0

03

Step 3. Final answer.

On simplifying the equation,

x1-x3+y1-y32=x-x02x1-x2+y1-y2=x-x02x12-2xx1+x2+y1-y2=x2-2xx0+x02x12-2xx1+y1-y2=-2xx0+x02x12-2xx1+y1-y2-x12+2xx1=-2xx0+x02-x12+2xx1y1-y2=-2xx0+2xx1+x02-x12y1-y2=-2xx0-x1+x02-x12

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