Chapter 9: Q. 28 (page 772)

Use Cartesian coordinates to express the equations for the parabolas determined by the conditions specified in Exercises 22–31.
$r = \frac{3}{1 + \cos θ}$

Short Answer

Expert verified

The equation is $y^{2} = 9 - 6 x .$

Step by step solution

Step 1. Given information.

The give equation is $r = \frac{3}{1 + \cos θ} .$

Step 2. Conversion.

Converting the polar co-ordinates into cartesian co-ordinates,

$r = \frac{3}{1 + \cos θ} r (1 + \cos θ) = 3 r + r \cos θ = 3 \sqrt{x^{2} + y^{2}} + r \cdot \frac{x}{r} = 3 [since r = \sqrt{x^{2} + y^{2}} and r \cos θ = x] \sqrt{x^{2} + y^{2}} + x = 3$

Step 3. Final answer.

On simplifying the equation,

$\sqrt{x^{2} + y^{2}} + x - x = 3 - x \sqrt{x^{2} + y^{2}} = 3 - x {(\sqrt{x^{2} + y^{2}})}^{2} = (3 - x)^{2} x^{2} + y^{2} = 9 + x^{2} - 6 x x^{2} + y^{2} - x^{2} = 9 + x^{2} - 6 x - x^{2} y^{2} = 9 - 6 x$

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Use Cartesian coordinates to express the equations for the parabolas determined by the conditions specified in Exercises 22–31.
$r = \frac{3}{1 + \cos θ}$

Short Answer

Step by step solution

Step 1. Given information.

Step 2. Conversion.

Step 3. Final answer.

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Use Cartesian coordinates to express the equations for the parabolas determined by the conditions specified in Exercises 22–31.r=31+cosθ

Short Answer

Step by step solution

Step 1. Given information.

Step 2. Conversion.

Step 3. Final answer.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Geometry

Calculus

Discrete Mathematics

Applied Mathematics

Decision Maths

Statistics

Study anywhere. Anytime. Across all devices.

Use Cartesian coordinates to express the equations for the parabolas determined by the conditions specified in Exercises 22–31.
$r = \frac{3}{1 + \cos θ}$