Chapter 9: Q 35. (page 731)

In Exercises 32–47 convert the equations given in polar coordinates to rectangular coordinates.
$θ = \frac{7 π}{6}$

Short Answer

Expert verified

The required equation is $y = \frac{\sqrt{3} x}{3}$ .

Step by step solution

Step 1. Given information.

The given equation in polar coordinates is:

$θ = \frac{7 π}{6}$

Step 2. Find the equation in rectangular coordinates.

Use the formula $\tan θ = \frac{y}{x}$ ,

$\tan (\frac{7 π}{6}) = \frac{y}{x} \frac{\sqrt{3}}{3} = \frac{y}{x} [\tan \frac{7 π}{6} = \frac{\sqrt{3}}{3}] 3 y = \sqrt{3} x y = \frac{\sqrt{3} x}{3}$

Therefore, the equation in rectangular coordinates is $y = \frac{\sqrt{3} x}{3}$ .

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In Exercises 32–47 convert the equations given in polar coordinates to rectangular coordinates.
$θ = \frac{7 π}{6}$

Short Answer

Step by step solution

Step 1. Given information.

Step 2. Find the equation in rectangular coordinates.

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In Exercises 32–47 convert the equations given in polar coordinates to rectangular coordinates.θ=7π6

Short Answer

Step by step solution

Step 1. Given information.

Step 2. Find the equation in rectangular coordinates.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Discrete Mathematics

Statistics

Applied Mathematics

Pure Maths

Geometry

Mechanics Maths

Study anywhere. Anytime. Across all devices.

In Exercises 32–47 convert the equations given in polar coordinates to rectangular coordinates.
$θ = \frac{7 π}{6}$