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Chapter 9: Q. 4 (page 745)

Translation of graphs: what is the relationship between the functions $y = f (x) a n d y = f (x) + k$ where k > 0

Short Answer

Expert verified

The graph of the function $y = f (x) + k$ will be above the graph of the function $y = f (x)$

Step by step solution

Given information

We are given two functions $y = f (x) a n d y = f (x) + k$

Explain the difference

The graph of the function will remain the same the difference will be of the position. the graph of the function $f (x) + k$ will be above the function y = f(x)

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Most popular questions from this chapter

Let $A > B > 0$ . Show that the distance from any point on the graph of the curve with equation $\frac{x^{2}}{A^{2}} + \frac{y^{2}}{B^{2}} = 1$ to the point $(- C, 0) is D_{2} = \frac{A^{2} + C x}{A^{2}}, where C = \sqrt{A^{2} - B^{2}} .$

In Exercises 48–55 convert the equations given in rectangular coordinates to equations in polar coordinates.

$y = - 3$

Use polar coordinates to graph the conics in Exercises 44–51.

$r = \frac{2}{4 + \sin θ}$

In Exercises 32–47 convert the equations given in polar coordinates to rectangular coordinates.
$θ = \frac{7 π}{6}$

Complete the square to describe the conics in Exercises $18 - 21$ .

$2 x^{2} + 4 x - y^{2} - 6 y - 23 = 0$

See all solutions

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Translation of graphs: what is the relationship between the functionsy=f(x)andy=f(x)+kwhere k > 0

Short Answer

Step by step solution

Given information

Explain the difference

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Most popular questions from this chapter

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Translation of graphs: what is the relationship between the functions $y = f (x) a n d y = f (x) + k$ where k > 0