Use your result from Exercise 68 to show that the arc length formula for a function y=f(x) is a special case of the arc length formula for a parametric curve.

Short Answer

Expert verified

ab1+f'(t)2dt

Step by step solution

01

Given information

y=f(x)

02

Calculation

Consider the function y=f(x)

For a parameter tthe function y=f(t)for some t[a,b]

The goal is to determine the curve's arc length.

If the curve Cis expressed by parametric equations x=f(t),y=y(t)on the interval [a,b]then the arc length is given by the formula,

abf'(t)2+g'(t)2dt

Thus, f(t)=xf'(t)=dxdt

g(t)=yg'(t)=dydt

Substituting the values of f'(t),g'(t)then the arc length is

Arc length =abddtx2+ddty2dt

=abdxdt2+dydt2dt

Then,

Arc length =ab1+dydt2dt

Arc length =ab1+f'(t)2dt[since , for some parameter t]Therefore the arc length of the curve y=f(t)is ab1+f'(t)2dt

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